[Stub] Newcomb problem as a prisoners’ dilemma/​anti-coordination game

You should always cooperate with an identical copy of yourself in the prisoner’s dilemma. This is obvious, because you and the copy will reach the same decision.

That justification implicitly assumes that you and your copy as (somewhat) antagonistic: that you have opposite aims. But the conclusion doesn’t require that at all. Suppose that you and your copy were instead trying to ensure that one of you got maximal reward (it doesn’t matter which). Then you should still jointly cooperate because (C,C) is possible, while (C,D) and (D,C) are not (I’m ignoring randomising strategies for the moment).

Now look at the Newcomb problem. You decision enters twice: once when you decide how many boxes to take, and once when Omega is simulating or estimating you to decide how much money to put in box B. You would dearly like your two “copies” (one of which may just be an estimate) to be out of sync—for the estimate to 1-box while the real you two-boxes. But without any way of distinguishing between the two, you’re stuck with taking the same action - (1-box,1-box). Or, seeing it another way, (C,C).

This also makes the Newcomb problem into an anti-coordination game, where you and your copy/​estimate try to pick different options. But, since this is not possible, you have to stick to the diagonal. This is why the Newcomb problem can be seen both as an anti-coordination game and a prisoners’ dilemma—the differences only occur in the off-diagonal terms that can’t be reached.