I don’t understand your response; but all I’m saying is that discrete universes are going to be measure zero in a multiverse which includes continua.
See my reply to Why no uniform weightings for ensemble universes? for a longer explanation of why not.
I don’t understand your response; but all I’m saying is that discrete universes are going to be measure zero in a multiverse which includes continua.
See my reply to Why no uniform weightings for ensemble universes? for a longer explanation of why not.