the exact same answer it would have output without the perturbation.
It always gives the same answer for the last digit?
Well we could always just set the last digit to 0 as a post-processing step to ensure perfect repeatability. But point taken, you’re right that most numerical algorithms are not quite as perfectly stable as I claimed.
It always gives the same answer for the last digit?
Well we could always just set the last digit to 0 as a post-processing step to ensure perfect repeatability. But point taken, you’re right that most numerical algorithms are not quite as perfectly stable as I claimed.