Sleeping Beauty is more subtle problem, so it’s less obvious why the application of centred possible worlds fails.
But in principle we can construct a similar argument. If we suppose that, in terms of the paper, ones epistemic state should follow function P’, instead of P on awakening in Sleeping Beauty we get ourselves into this precarious situation:
P’(Today is Monday|Tails) = P’(Today is Tuesday|Tails) = 1⁄2
as this estimate stays true for both awakenings:
P’(At Least One Awakening Happens On Monday|Tails) = 1 - P’(Today is Tuesday|Tails)^2 = 3⁄4
While the actual credence should be 100%. Which gives an obvious opportunity to money pump the Beauty by bets on awakenings on the days in the experiment.
This problem, of course, doesn’t happen when we simply keep using function P for which “Today is Monday” and “Today is Tuesday” are ill-defined, but instead:
P(Monday Awakening Happens in the Experiment|Tails) = 1
P(Tuesday Awakening Happens in the Experiment|Tails) = 1
and
P(At Least One Awakening Happens On Monday|Tails) = P(Monday Awakening Happens in the Experiment|Tails) = 1
But again, this is a more subtle situation. The initial example with money in envelope is superior in this regard, because it’s immediately clear that there is no coherent value for P’(Money in Envelope 1) in the first place.
Sleeping Beauty is more subtle problem, so it’s less obvious why the application of centred possible worlds fails.
But in principle we can construct a similar argument. If we suppose that, in terms of the paper, ones epistemic state should follow function P’, instead of P on awakening in Sleeping Beauty we get ourselves into this precarious situation:
P’(Today is Monday|Tails) = P’(Today is Tuesday|Tails) = 1⁄2
as this estimate stays true for both awakenings:
P’(At Least One Awakening Happens On Monday|Tails) = 1 - P’(Today is Tuesday|Tails)^2 = 3⁄4
While the actual credence should be 100%. Which gives an obvious opportunity to money pump the Beauty by bets on awakenings on the days in the experiment.
This problem, of course, doesn’t happen when we simply keep using function P for which “Today is Monday” and “Today is Tuesday” are ill-defined, but instead:
P(Monday Awakening Happens in the Experiment|Tails) = 1
P(Tuesday Awakening Happens in the Experiment|Tails) = 1
and
P(At Least One Awakening Happens On Monday|Tails) = P(Monday Awakening Happens in the Experiment|Tails) = 1
But again, this is a more subtle situation. The initial example with money in envelope is superior in this regard, because it’s immediately clear that there is no coherent value for P’(Money in Envelope 1) in the first place.