Ah, I had misread the quote, and confused P(A|B) with P(B|A). Nevertheless, I think your objection is with the statement that P(A|B) > P(A|~B).
Ah, I had misread the quote, and confused P(A|B) with P(B|A). Nevertheless, I think your objection is with the statement that P(A|B) > P(A|~B).