Diffractor comments on Finite Factored Sets: Polynomials and Probability

[Diffractor]

In the proof of Lemma 3, it should be

“Finally, since ${\chi }_C^F(z,z)=z$, we have that ${\text{poly}}_C^F\left(z\right)\cdot {\text{poly}}_{B\setminus C}^F\left(z\right)=Q_z^F$.

Thus, $Q_z^F\cdot Q_{x\cap y\cap z}^F$ and $Q_{x\cap z}^F\cdot Q_{y\cap z}^F$ are both equal to ${\text{poly}}_C^F(x\cap z)\cdot {\text{poly}}_{B\setminus C}^F(y\cap z)\cdot {\text{poly}}_C^F\left(z\right)\cdot {\text{poly}}_{B\setminus C}^F\left(z\right)$.

instead.

[Scott Garrabrant]

Fixed, Thanks.