p.b. comments on Jacob_Hilton’s Shortform

[p.b.]

How does this coefficient relate to the maximal slope (i.e. at the 50%-x)?

[Jacob_Hilton]

The gradient of $\sigma (-\beta x)$ at $x=0$ is $-\frac{1}{4}\beta$, which corresponds to a maximally negative slope of $-\frac{\ln \left(2\right)}{4}\beta \approx -17\%\times \beta$ per doubling, where $\beta \approx 1$ is the rightmost column in my table.

[p.b.]

Thanks!