Hmm. So T is an acceptor, A is an attacker. A(T) is an infinite sequence of symbols produced after examining T’s source code, and T(A(T)) = ⊥ means T never rejects the sequence. Then what I was asserting is ¬∃A:∀T:T(A(T)) = ⊥. What you’re asking now is whether ∀T:∃A:T(A(T)) = ⊥ and I can’t immediately work out the answer.
Hmm. So T is an acceptor, A is an attacker. A(T) is an infinite sequence of symbols produced after examining T’s source code, and T(A(T)) = ⊥ means T never rejects the sequence. Then what I was asserting is ¬∃A:∀T:T(A(T)) = ⊥. What you’re asking now is whether ∀T:∃A:T(A(T)) = ⊥ and I can’t immediately work out the answer.