Ah. Very good point. I hadn’t actually checked that hyperbolic discounting would have the property of integrating to a constant. I assumed that since it falls faster than exponential, the integral would be smaller—but it only falls faster initially.
Ah. Very good point. I hadn’t actually checked that hyperbolic discounting would have the property of integrating to a constant. I assumed that since it falls faster than exponential, the integral would be smaller—but it only falls faster initially.