This is a special case of a crisp infradistribution: Q(A|B)=t is equivalent to Q(A∩B)=tQ(B), a linear equation in Q, so the set of all Q’s satisfying it is convex closed.

Thanks! That’s useful to know.

This is a special case of a crisp infradistribution: Q(A|B)=t is equivalent to Q(A∩B)=tQ(B), a linear equation in Q, so the set of all Q’s satisfying it is convex closed.

Thanks! That’s useful to know.