That’s not correct at all. sum(1/2^n)[1:infinity] = 1.
Oops, misread that as sum(1/(2n))[1:infinity] (which it wasn’t), my bad.
That’s not correct at all. sum(1/2^n)[1:infinity] = 1.
Oops, misread that as sum(1/(2n))[1:infinity] (which it wasn’t), my bad.