Argument 2 is right. Here is how I think about it. If I am holding one ace the probability it is a spade is 1⁄2 (there are only two aces). If I am holding two aces the probability that one selected randomly is the spade is also 1⁄2. The cases aren’t distinguished by the expected response to the question “Do you hold the ace of spades?” so that information cannot possibly be used to update the prior answer of 1⁄5.
Argument 2 is right. Here is how I think about it. If I am holding one ace the probability it is a spade is 1⁄2 (there are only two aces). If I am holding two aces the probability that one selected randomly is the spade is also 1⁄2. The cases aren’t distinguished by the expected response to the question “Do you hold the ace of spades?” so that information cannot possibly be used to update the prior answer of 1⁄5.