even if complement(null hypothesis) were well defined, the sum could fall anywhere in the closed interval [0, 2].
Huh? P(X|Y) + P(X|Y’) = P(X) and an event that has already occurred has a probably of one. Am I missing something?
Huh? P(X|Y) + P(X|Y’) = P(X) and an event that has already occurred has a probably of one. Am I missing something?