Sorry for the delay. As both you and TheMcDouglas have mentioned; yea, this relies on $H(C|X) = 0$. The way I’ve worded it above is somewhere between misleading and wrong, have modified. Thanks for pointing this out!
Sorry for the delay. As both you and TheMcDouglas have mentioned; yea, this relies on $H(C|X) = 0$. The way I’ve worded it above is somewhere between misleading and wrong, have modified. Thanks for pointing this out!