Robin, how is the transition
y = e^t → dy/dt = e^t
=>
dy/dt = e^y → y = -ln(C—t) → dy/dt = 1/(C—t)
“adding one more power to the derivative in the growth equation”?
I’m not sure what that phrase you used means, exactly, but I wonder if you may be mis-visualizing the general effect of what I call “recursion”.
Or what about y = t^2 ⇒ dy/dt = y^2, etc. Or y = log t ⇒ dy/dt = log y, etc.
Like I said, this doesn’t necessarily hockey-stick; if you get sublinear returns the recursified version will be slower than the original.
Robin, how is the transition
y = e^t → dy/dt = e^t
=>
dy/dt = e^y → y = -ln(C—t) → dy/dt = 1/(C—t)
“adding one more power to the derivative in the growth equation”?
I’m not sure what that phrase you used means, exactly, but I wonder if you may be mis-visualizing the general effect of what I call “recursion”.
Or what about y = t^2 ⇒ dy/dt = y^2, etc. Or y = log t ⇒ dy/dt = log y, etc.
Like I said, this doesn’t necessarily hockey-stick; if you get sublinear returns the recursified version will be slower than the original.