I assume you had to pick a range.
A mathematician can probably give a better way to pick without setting an upper bound, but I did:
(current year + (p/(1-p)) where .5 < p < 1.0
It was happy to accept roman numerals (and presumably any input at all)
I assume you had to pick a range.
A mathematician can probably give a better way to pick without setting an upper bound, but I did:
(current year + (p/(1-p)) where .5 < p < 1.0
It was happy to accept roman numerals (and presumably any input at all)