you mean the Nâ€™th root of 2 right?, which is what I called the null predictor and divided Scott predictions by in the code:

random_predictor = 0.5 ** len(y)

which is equivalent to 0.5N where N is the total number of predictions

you mean the Nâ€™th root of 2 right?, which is what I called the null predictor and divided Scott predictions by in the code:

which is equivalent to 0.5N where N is the total number of predictions