If so, consider X = “free will exists”. One could argue that the term “free will” is defined such that it is impossible to detect it, or to prove that it exists. But if one could prove that the many worlds interpretation of quantum mechanics is correct, that would constitute a disproof of X. Then P(will_be_proven(X)) / (P(will_be_proven(X)) + P(will_be_disproven(X))) = 0.
This has to be one of the worst examples I’ve ever seen that wasn’t actively trying to push an agenda.
This has to be one of the worst examples I’ve ever seen that wasn’t actively trying to push an agenda.