Either way, if (A) gets significantly reduced as a probability, and we have no reason to simultaneously reduce the probability of (D) (or adjust the relative likelihood of the remaining probabilities in a manner that disadvantages (D)), then (D)’s estimated probability must increase by a factor analogous to the weight that (A) previously held.
E too, obviously, likewise with C.
But the question that began this thread was about (D), not about (C) or any Es. So that’s what I’m talking about.
End of conversation.
Seriously? You got offended after I patiently spend long paragraphs explaining basic probability to you? And you don’t even bother answering my question, after I answer all of yours?
I’ll keep this in mind next time I am tempted to respond to you.
Why D in particular? Why not E?
End of conversation.
E too, obviously, likewise with C. But the question that began this thread was about (D), not about (C) or any Es. So that’s what I’m talking about.
Seriously? You got offended after I patiently spend long paragraphs explaining basic probability to you? And you don’t even bother answering my question, after I answer all of yours?
I’ll keep this in mind next time I am tempted to respond to you.