I don’t think you have the dependencies quite right, because you can actually use more of the information than you do above to restrict the population from which you draw.
The real underlying population you should draw on seems to to be the population of fathers with exactly two children, of which one might be a boy born on Tuesday.
p(a two boy family given one brother was born on Tuesday) = (p(one brother born on Tuesday in a in two-boy family)) (p(two boys in 2 person families)) / p(out of all two person families, having one be a boy born on Tuesday)
which is if we say Tuesday birth is 1⁄7 and boy is 1⁄2,
(2/7) (1/4) / (2/14) = 1⁄2 so the Tuesday datum drops out.
I know no one is likely to do this, but consider the safeguards taken by auto racing drivers. They are required to wear a helmet. For high speed driving helmets on all in the car would cut the death rate. That said, I doubt anyone will do this, as the inconvenience is great for a small payoff.