But in probability theory, absence of evidence is always evidence of absence. If E is a binary event and P(H|E) > P(H), “seeing E increases the probability of H”; then P(H|~E) < P(H), “failure to observe E decreases the probability of H”. P(H) is a weighted mix of P(H|E) and P(H|~E), and necessarily lies between the two.
Yes, see this for details on why this is so.
Thanks! The second to last paragraph from your EY citation was exactly what I was looking for.