If you know the derivative at 0 is 1, then you know the value of pi… just sayin’.
That’s not strictly true, seeing as...
...but I agree that general-shape + derivative-at-zero is not really enough to form estimate of pi.
If you know the derivative at 0 is 1, then you know the value of pi… just sayin’.
That’s not strictly true, seeing as...
%5En}{(2n+1)!}\,x%5E{2n+1})...but I agree that general-shape + derivative-at-zero is not really enough to form estimate of pi.