Willingness to pay Omega depends on having arbitrarily high confidence in his predictions
No. Paying is the winning strategy in the version where the predictor is correct only with probability, say, 0.8, too. ie.
P(o=AWARD) = 0.8*P(a=PAY)+0.2*P(a=REFUSE)
(blink)
You’re right; I’m wrong. Clearly I haven’t actually been thinking carefully about the problem.
Thanks.
No. Paying is the winning strategy in the version where the predictor is correct only with probability, say, 0.8, too. ie.
(blink)
You’re right; I’m wrong. Clearly I haven’t actually been thinking carefully about the problem.
Thanks.